{"id":354,"date":"2023-12-04T15:12:19","date_gmt":"2023-12-04T15:12:19","guid":{"rendered":"https:\/\/www.supertal.com\/?p=354"},"modified":"2023-12-04T20:32:53","modified_gmt":"2023-12-04T20:32:53","slug":"problemas-de-quimica-equilibrio-quimico","status":"publish","type":"post","link":"https:\/\/www.supertal.com\/?p=354","title":{"rendered":"Problemas de qu\u00edmica: Equilibrio qu\u00edmico."},"content":{"rendered":"\n<p>Enunciado: <strong>Al pasar vapor de agua sobre hierro al rojo, se produce una reacci\u00f3n qu\u00edmica en la que se produce \u00f3xido ferroso f\u00e9rrico e hidr\u00f3geno. Medido a la temperatura de 200\u00baC los componentes gaseosos del equilibrio tienen las siguientes presiones parciales: 4,6 mmHg para el agua y 95,9 mmHg para el hidr\u00f3geno. 1.- Cuando la presi\u00f3n parcial del vapor de agua es 9,3 mmHg, \u00bfCu\u00e1nto vale la del hidr\u00f3geno?. 2.- Calcular la presi\u00f3n parcial del hidr\u00f3geno y agua cuando la presi\u00f3n total sea de 760 mmHg.<\/strong><\/p>\n\n\n\n<p>Primero planteamos la ecuaci\u00f3n de la reacci\u00f3n y a ajustamos:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><a href=\"https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-4.png\"><img loading=\"lazy\" decoding=\"async\" width=\"215\" height=\"32\" src=\"https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-4.png\" alt=\"\" class=\"wp-image-355\"\/><\/a><\/figure><\/div>\n\n\n<p>Con los datos iniciales de las presiones parciales a 200\u00baC podemos calcular la constante de equilibrio de la reacci\u00f3n:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><a href=\"https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-5.png\"><img loading=\"lazy\" decoding=\"async\" width=\"336\" height=\"87\" src=\"https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-5.png\" alt=\"\" class=\"wp-image-356\" srcset=\"https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-5.png 336w, https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-5-300x78.png 300w\" sizes=\"(max-width: 336px) 100vw, 336px\" \/><\/a><\/figure><\/div>\n\n\n<p>De esta podemos despejar el valor de la presi\u00f3n parcial del hidr\u00f3geno cuando la del agua es 9,3 mmHg seg\u00fan el primer apartado del problema:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><a href=\"https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-6.png\"><img loading=\"lazy\" decoding=\"async\" width=\"597\" height=\"46\" src=\"https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-6.png\" alt=\"\" class=\"wp-image-357\" srcset=\"https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-6.png 597w, https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-6-300x23.png 300w\" sizes=\"(max-width: 597px) 100vw, 597px\" \/><\/a><\/figure><\/div>\n\n\n<p>Para resolver la segunda parte, haremos uso de la ecuaci\u00f3n general de los gases:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><a href=\"https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-7.png\"><img loading=\"lazy\" decoding=\"async\" width=\"619\" height=\"199\" src=\"https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-7.png\" alt=\"\" class=\"wp-image-358\" srcset=\"https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-7.png 619w, https:\/\/www.supertal.com\/wp-content\/uploads\/2023\/12\/image-7-300x96.png 300w\" sizes=\"(max-width: 619px) 100vw, 619px\" \/><\/a><\/figure><\/div>","protected":false},"excerpt":{"rendered":"<p>Enunciado: Al pasar vapor de agua sobre hierro al rojo, se produce una reacci\u00f3n qu\u00edmica en la que se produce \u00f3xido ferroso f\u00e9rrico e hidr\u00f3geno. Medido a la temperatura de 200\u00baC los componentes gaseosos del equilibrio tienen las siguientes presiones parciales: 4,6 mmHg para el agua y 95,9 mmHg para el hidr\u00f3geno. 1.- Cuando la &hellip; <a href=\"https:\/\/www.supertal.com\/?p=354\" class=\"more-link\">Seguir leyendo <span class=\"screen-reader-text\">Problemas de qu\u00edmica: Equilibrio qu\u00edmico.<\/span> <span class=\"meta-nav\">&rarr;<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[27],"tags":[],"class_list":["post-354","post","type-post","status-publish","format-standard","hentry","category-quimica"],"_links":{"self":[{"href":"https:\/\/www.supertal.com\/index.php?rest_route=\/wp\/v2\/posts\/354"}],"collection":[{"href":"https:\/\/www.supertal.com\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.supertal.com\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.supertal.com\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.supertal.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=354"}],"version-history":[{"count":1,"href":"https:\/\/www.supertal.com\/index.php?rest_route=\/wp\/v2\/posts\/354\/revisions"}],"predecessor-version":[{"id":359,"href":"https:\/\/www.supertal.com\/index.php?rest_route=\/wp\/v2\/posts\/354\/revisions\/359"}],"wp:attachment":[{"href":"https:\/\/www.supertal.com\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=354"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.supertal.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=354"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.supertal.com\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=354"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}